What is an equation of the line that is parallel to y=9-5x and passes though (0,8)?

y = 8-5x

Step-by-step explanation:

When two lines are parallel, it means their gradients are the same.

from the given equation

y = 9-5x

and comparing with the general equation of a line

y = mx+c, where m is the gradient, and c is the y-intercept,

m = -5

you can form a line parallel to that using the points (0,8)

(y-8)/(x-0)= -5

this would give you

y = 8-5x

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.