Mark just got his commercial driver's license and is starting a new career as a truck driver.
getting trained and licensed involved a one-time cost of $422. gas and insurance end up
costing him $3 per mile. for his first delivery, mark will get paid $400 plus $5 per mile that
he drives. if he drives a certain distance on this delivery, mark will break even, making back
all the money he had to spend. how much would both the costs and the earnings be? what
distance would he have to drive?

Answer to break even, cost = earnings= $455, number of miles to cover is 11

Step-by-step explanation: cost =422+3x, where x= number of miles covered

Earnings=400+5x

St break even, cost = earnings, then solving the linear equation, by collecting like terms, and dividing through by 22. x=11, the Pu x=11 in the either the cost or earnings expressing to get 455

sites:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .