3x^2 β 12x β 2y - 2 = 0
-3y^2 β 22y - 19 = 3x^2 β 12x...
Mathematics, 09.12.2019 04:31 logicalness243
3x^2 β 12x β 2y - 2 = 0
-3y^2 β 22y - 19 = 3x^2 β 12x
Answers: 1
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