Need solving with working much appreciated

i. g = 70°

ii. x = 85°

Step-by-step explanation:

Given:

Let first we name the triangle

i. ) Δ PQR , m∠ PRQ = 40°

ii. ) Δ ABC is a right angle at B and a line B- D-C

       m∠ DAC = 25°

       m∠ ACD = 60°

       m∠ BDA = x°

To Find:

i. g = ?

ii. x = ?

Solution:

i.

In Δ PQR , PR ≅ QR ...........{Given]

∴ Δ PQR is an Isosceles Triangle.

c.........{ Base angles of Isosceles triangle are equal }

∴ m∠ PQR = m∠ RPQ = g

Now sum of all the angles in a triangle is 180°

∴ m∠ PQR + m∠ RPQ + m∠ PRQ = 180°....{Angle sum property of Triangle}

∴ g = 70°

ii.

We know sum of all the angles in a triangle is 180°

In Δ DAC

m∠ DAC + m∠ ACD + m∠ ADC = 180°.....{Angle sum property of Triangle}

Now By Linear Pair Angle Property

m∠ ADB + m∠ ADC = 180° ........{Linear Pair Angle Property}

∴ x = 85°

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: