Question 4

there are 39 chocolates in a box, all identically shaped. there 16 are filled with nuts, 13 with caramel, and 10 are solid

chocolate. you randomly select one piece, eat it, and then select a second piece. find the probability of selecting a nut

chocolate followed by a caramel chocolate.

The probability of selecting nut chocolate followed by a caramel chocolate is

=(15/38)(13/39)

=15/144

=.1315

Step-by-step explanation

The probability of selecting first piece as a nut chocolate is

Nut chocolate = 16

total chocolates = 39

probability of  nut chocolate=16/39

The probability of selecting first piece as a nut chocolate is 15 out of 38

=15/ 38

probability of caramel chocolate = 13/39

then 15/38 th time you select a nut chocolate by caramel

So

=(15/38)(13/39)

=15/144

=.1315

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4