Suppose x and y have the following joint probability mass function. p ( 1 , 1 ) = . 10 , p ( 1 , 2 ) = . 12 , p ( 1 , 3 ) = . 16 p ( 2 , 1 ) = . 08 , p ( 2 , 2 ) = . 12 , p ( 2 , 3 ) = . 10 p ( 3 , 1 ) = . 06 , p ( 3 , 2 ) = . 06 , p ( 3 , 3 ) = . 20 find e [ x ] and e [ y ] . find v a r ( x ) and v a r ( y ) . find c o v ( x , y ) . find the correlation between x and y .

what are you trying to solve here

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

x = 3 ± √(5+y)