Two buses depart two cities moving in the same direction. the speed of the first bus is 54 mph which is 60% of the speed of the second bus. the faster bus caught up to the other bus one hour and thirty minutes after the departure. will give brainliest

The second city is 54 miles behind the first city

Step-by-step explanation:

The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.  

The speed of the second bus is then 54/0.6 = 90 mph

When 1 and a half hour has passed, the first bus has moved a distance of

= 81 miles

The second bus (behind the first bus) has moved

= 135 miles

The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city

So, the second city is 54 miles behind the first city

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)