Rachel is painting one wall of her room with a pattern of squares. she want to alternate between red squares with an area of 25 square inches and blue squares with an area of 16 inches.
part a: find the side length of each square. show or explain your work.
part b: if she has enough room to place 12 of each type of square with not space between them, how long is the wall? explain your reasoning.

Part A.  5 in and 4 in

Part B. 108 in

Step-by-step explanation:

Part A.  

A (square) = side², then side = √(A)

A1 = 25 in², then side1 = √(25) = 5 in

A2 = 16 in², then side2 = √(16) = 4 in

Part B.

12*5 in + 12 * 4 in = 60 + 48 = 108 in

length of the wall = 108 in

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option