About 5% of the population has a particular genetic mutation. 1000 people are randomly selected.

find the standard deviation for the number of people with the genetic mutation in such groups of 1000.

Step-by-step explanation:

Let, X = Number of people with the genetic mutation in such groups of 1000

Here, we get a random variable X with binomial distribution with parameters

n = 1000 and p = 5 % = 0.05

So,

X bin ( 1000 , 0.05)

so V(X) or Variance(X) =

                                     = 47.5

So, SD(X) = Standard Deviation(X) =

24

step-by-step explanation:

i assuming that 2 sides are 6 the other 2 sides are 4 cm so 6 times 4 is 24 : )