Find the least number which when divided by 25 45 60 leaves a remainder to 20

a=920

Step-by-step explanation: X :  Y =Z (R) ; Z< Y

a : 25= x(r=20) ; 20<x

a:45= y(r=20) ; 20<y

a:60=z (r = 20);  20<z

a=25x+20(1)

a=45y+20(2)

a=60z+20(3)

(1);(2);(3)⇒a-20 ∈ [25,45, 60]

25=5²

45=3²x 5

60=2²x 3 x 5

[25, 45, 60]=2²x 3² x 5²=900⇒

⇒a-20∈{0, 900, 1800, , 900K}/+20

 a ∈ {20, 920, 1820,, 920K}

a=920

920: 25=36 (r=20)-True=>

a=920 is the smallest  number that divided by 25, 45 , 60 leaves a  remainder of 20

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}