Need
a stadium has 46,000 seats. seats sell for $42 in section a, $24 in section b, and $18 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,467,600 from each sold-out event. how many seats does each section hold?

The answer to your question is:

A = 23000

B = 14600

C = 8400

Step-by-step explanation:

Data

A = $42

B = $24

C = $18

                  A = B + C

Equations

                42A + 24B + 18C = 1,467,600

                A + B + C = 46,000

Process

                A + A = 46,000

               2A = 46000

               A = 23000

             B + C = 23000

             B = 23000 - C

              42(23000) + 24(23000 - C) + 18C = 1,467,600                  

             966000 + 552000 - 24C + 18C = 1467600

             -6C = -50400

              C = 8400

              B = 23000 - 8400

              B = 14600

boxplot e is the answer

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.