The half-life of iodine-124 is 4 days. a technician measures a 40-mci sample of iodine-124. how many half-lives of iodine-124 occur in 16 days? how much iodine-124 is in the sample 16 days after the technician measures the original sample?

The answer to your question is:

a) 4 half-life

b)  2.5 mCi

Step-by-step explanation:

Half-life of iodine 124 is 4 days

# of half- lives in 16 days = ?

Process

                           0 days  0 half-life

                           4 days 1 half life

                           8 days  2 halves lives

                         12 days     3 halves lives

                         16 days     4 halves lives                            

b)                        40 mCi   initially

                          20 mCi   1 half life

                          10 mCi      2 half life

                           5 mCi       3 half life

                         2.5 mCi     4 half life

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40