Me .find the coordinates of j' after a reflection across the line x=1 and then across the x axis.

  J'' = (0, 1)

Step-by-step explanation:

For M being the midpoint of the segment JJ', its coordinates are the average of those of J and J':

  M = (J + J')/2

We can rearrange this to find J' from M and J.

  2M = J + J'

  J' = 2M - J

For a reflection across the line x = 1, the x-coordinate of M is 1. For a reflection across the line y = 0 (the x-axis), the y-coordinate of M is 0. Your double reflection amounts to a reflection across the point (1, 0).

The the image of J after the two reflections is ...

  J' = 2(1, 0) -(2, -1) = (2·1-2, 2·0+1)

  J' = (0, 1)

_____

In the attached image, the point after the second reflection is called J".

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

50- 250 is correct i did that one too

step-by-step explanation: