45 !
let f be the function defined by f(x)=(ax^2+be+2)/(2x^2-8) where a and b are constants. the graph of f has a horizontal asymptote at y=3 and f has a removable discontinuity at x=2.
at what value of x does f have discontinuity due to a vertical asymptote? give a reason for your answer.

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step-by-step explanation:

good luck on your studies! : )

david edward.

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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