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Mathematics, 17.09.2019 19:30 julio38

The equation of line lm is 5x βˆ’ y = βˆ’4. what is the equation of a line perpendicular to line lm in slope-intercept form that contains point (βˆ’3, 2)?
y = 5x + 13
y = negative one fifthx + seven fifths
y = negative one fifthx βˆ’ seven fifths
y = 5x βˆ’ 17

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