2. A plane traveled from California and back. It took one hour longer on the way out than it
did on the way back. The plane's average speed out was 300 mph. The average speed on the
way back was 350 mph. How many hours did the trip out take?
O A. 13 hours
B. 7 hours
O C. 8 hours
OD. 6 hours

Option D is the correct answer.

Step-by-step explanation:

the time out.

Time taken for back = t-1

We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.

That is

Dividing both equations

Time taken for back = t-1 = 7-1 = 6 hours.

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fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/