An office has 30 computers. seventeen of the 30 are macintosh, and the remaining thirteen are windows. two computers are randomly selected without replacement. what is the probability that the sample contains exactly one windows machine and exactly one macintosh? if needed, round to four decimal places. pr(one widows and one macintosh) =

0.5085

Step-by-step explanation:

Given that an office has 30 computers. Seventeen of the 30 are Macintosh, and the remaining thirteen are windows.

When two computers are randomly selected without replacement

no of ways of selection =

No of ways of selecting one window and one Mac =

Prob that the sample contains exactly one windows machine and exactly one Macintosh=

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?