The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation $1200. the daily revenue totals for the next 30 days will be monitored. what is the probability that the mean daily revenue for the next 30 days will exceed $7500? round to four decimal places. a. 0.9131 b. 0.0869 c. 0.9147 d. 0.0853

D.0.0853

Step-by-step explanation:

We assume that the daily revenue totals for the next 30 days will be follow a normal distribution.

Given : Population mean :

Standard deviation :

Sample size : n=30

Let X be the random variable that represents the daily revenue .

Z-score :

For x=$7500

By using the standard normal distribution table for z , we have

Hence, the probability that the mean daily revenue for the next 30 days will exceed $7500= 0.0853=

idk

step-by-step explanation:

i don't know

it is not that hard all u have to do is plot the graph

step-by-step explanation: