Consider the reaction below. h2(g) + co2(g) mc013-1.jpg h2o(g) + co(g) at equilibrium at 600 k, the following are true. [co2] = 9.5 x 10-4 m [h2] = 4.5 x 10-2 m [h2o] = 4.6 x 10-3 m [co] = 4.6 x 10-3 m what is the value of the equilibrium constant for this reaction in correct scientific notation? 4.9 x 10-3 4.9 x 10-2 4.9 x 10-1 4.9 x 103

Ans: c) 4.9 *10-1

Given:

Concentrations of the reactants and products-

[CO2] = 9.5 x 10-4 M

[H2] = 4.5 x 10-2 M

[H2O] = 4.6 x 10-3 M

[CO] = 4.6 x 10-3 M

To determine:

The equilibrium constant K

Explanation:

The given reaction is:

H2(g) + CO2(g) ↔ H2O(g) + CO(g)

The equilibrium constant is given as:

h let me think

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.