v=4/3? r^2 suppose that, for the sphere in the video, instead of being told how fast the radius is changing, we're told that the volume is increasing at a constant rate of dv/dt=4 cubic centimeters per second. how fast is the radius increasing at the instant when the radius is r=10 centimeters? dr/dt= centimeters per second.
instead of thinking about the volume, suppose that we are interested in how the surface area of the sphere is changing. use the surface area formula s=4? r^2 to determine how fast the surface area is changing at the instant when the radius is r=20 cm and the radius is increasing at dr/dt=2 centimeters per second. ds/dt=
how to get this answer?

cm per second

Volume of sphere is increasing at a constant rate

cubic centimeters per second

We have to find the rate of  radius at which increasing

when r= 10 cm

Differentiating w.r.t time

cm per second

Now ,we are given that surface area of sphere

Differentiate w.r.t time then we get

cm per second

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

associative property hopes this ! : )

step-by-step explanation: