Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ± 3/5x.
answers:
a) ((y^2)/)/25)=1
b) ((y^2)/)/36)=1
c) ((y^2)/)/9)=1
d) ((y^2)/)/100)=1

a

step-by-step explanation:

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.

13664

step-by-step explanation:

=cross multiply

=100 x = 13664