Juan invested $3,100 in an account paying an interest rate of 3.6% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 19 years?

A=6143.54( to the nearest dollar A=6144)

Step-by-step explanation:

A=Pe^(r(t))

P=3100 r=0.036 t=19

A=3100e^0.036(19)

A=3100e^(0.684)

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: