The probability that a train leaves on time is 0.8. the probability that the train arrives on time and leaves on time is 0.24. what is the probability that the train arrives on time, given that it leaves on time?

Answer is 0.3

Step-by-step explanation:

Let the probability that the train arrives on time. = p

The probability that the train leaves on time = 0.8

The probability that the train leaves on time and arrives on time = 0.24

Then the equation will be:

0.8 * p = 0.24

Move the constant value to the R.H.S

p = 0.24/0.8

p = 0.3

Thus the probability is 0.3

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

54.864 meters

step-by-step explanation: