Assume that women's heights are normally distributed with a mean given by mu equals 62.3 in, and a standard deviation given by sigma equals 2.4 in.(a) if 1 woman is randomly selected, find the probability that her height is less than 63 in.(b) if 47 women are randomly selected, find the probability that they have a mean height less than 63 in.

a)  0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean :

Standard deviation :

The formula for z -score :

a) Sample size = 1

For x= 63 in. ,

The p-value =

Thus, the probability is approximately = 0.6141

b)  Sample size = 47

For x= 63 ,

The p-value =

Thus , the probability that they have a mean height less than 63 in =0.9772.

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation:

$3720

step-by-step explanation:

taxable income = $31000

as per the 2018-2019 us tax bracket, the tax rate is 12% for an individual whose taxable income is between $9,526 to $38,700.

so, the tax to be paid by him = 12% of 31000

= 0.12 * 31000     [12% converted to decimal as 0.12]

= $3720