Find the smallest positive integer n such that 6000n and is a perfect cube

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

answer: 2 and 1

step-by-step explanation: got this question

by definition, an arc subtended by a central angle of some given measure has the same measure. so .