Five samples of size 4 were taken from a process. a range chart was developed that had lclr = 0 and uclr = 2.50. similarly, an average chart was developed with the average range from the five samples, with lcl = 15.0 and ucl = 22.0. the ranges for each of the five samples were 1.75, 2.22, 2.35, 2.04, and 2.30, respectively. the values of the sample average for each sample were 19.5, 22.3, 17.4, 20.1, and 18.9, respectively. what can you tell management from this analysis?

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!

14

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.