Adog and a cat are 200 meters apart when they see each other. the dog can run at a speed of 30 m/sec, while the cat can run at a speed of 24 m/sec.
a
how soon will they meet if they simultaneously start running towards each other?

with this question! i need the answer by tomorrow. you!

The dog will catch the cat at  33.33 sec

Step-by-step explanation:

Let

x> distance the cat runs before being caught by the dog,

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/24=(200+x)/30

30x=24(200+x)

30x=4,800+24x

30x-24x=4,800

x=4,800/6=800 m

t=d/v=800/24=33.33 sec

or

t=(800+200)/30=1,000/30=33.33 sec

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9