Which system of linear inequalities has the point (3,-2) in its solution set?
a. y < -3
y ≤ 2/3x - 4
b. y > -3
y ≥ 2/3x - 4
c. y < -3
y ≥ 2/3x - 4
d. y > -2
y ≤ 2/3x - 4

(the answers come with graphs but sorry i couldn't find a way to put them all in)

Option B.

Step-by-step explanation:  

we know that

If a ordered pair is a solution of the system of inequalities

then

the ordered pair must satisfy both inequalities of the system

Verify each case

Case A) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

----> is not true

therefore

The ordered pair is not a solution of the system A

Case B) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

----> is true

Inequality 2

----> is true

therefore

The ordered pair is a solution of the system B

Case C) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

----> is not true

therefore

The ordered pair is not a solution of the system C

Case D) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

----> is not true

therefore

The ordered pair is not a solution of the system D

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation:

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest