Water is flowing in a circular pipe varying cross-sectional area, and at all points the water completely fills the pipe. a) at one point in the pipe the radius is 0.210 m. what is the speed of the water at this point if water is flowing into this pipe at a steady rate of 1.10 m3/s? b) at a second point in the pipe the water speed is 2.80 m/s. what is the radius of the pipe at this point?

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

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step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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