Find cos 0, tan 0, csc 0, sec 0, cot 0

tan is really sin/cos and cot is really cos/sin so just put what they really mean in their place to make it > sin 0/cos 0 + cos0/sin 0 = sec 0 csc 0 then sec 0 is really 1/sin 0 and csc 0 is really 1/cos 0 so you just sove by cross multiply and multiply bottom together to get sin^2 0 + cos^2 0/sin 0 cos 0 then simplify to get 1/sin 0 cos 0 which is really 1/sin 0 1/cos 0 = sec 0 csc 0.  ㄒɦĄŊĸ ĦØφĒ ĮŤ ɧėŁP ♡✧♡

idk lol xd

step-by-step explanation:

ez do it yourself lazy

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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