Find the equation of each line from the given information. write the equation in standard form. show your work for. the line contains the points (3.0) and (4,6)

y=6x-18

Step-by-step explanation:

To find the standard equation of a linear relationship given two points, you need to find the slope and y intercept.

slope is change in y divided by change in x.

(6-0)/(4-3)

(6)/(1)

The slope of the line is 6.

We can plug this in along with x and y values from a given coordinate into the standard equation format to solve for b, the y intercept.

y=mx+b

y=0

x=3

m=6

0=6(3)+b

0=18+b

b=-18

now we know that the y intercept is (0,-18). The standard equation would be y=6x-18

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

594 square inches

step-by-step explanation:

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