Cameron flips two coins and then spins the spinner below.

what is the probability of having two different outcomes on the coins and spinning an odd number?

a. 1/16
b. 1/8
c. 1/4
d. 1/2

the numbers on the spinner are 1, 2, 3, and 4.

C: 1/4

Step-by-step explanation:

We have tow events: flipping the coin and spinning the number. As both are independent -there are no reason to expect that the result of the coin affect the spinning or vice-versa- we can treat the probabilities as independents.

First, lets get the probability of flipping two coins and get different outcomes.

If we flip 2 coins our universe is not big. Our possible outcomes are (face is F and tail is T):

F F, F T, T F, T T

So, we have 4 possible outcomes. Which of these we want? Only 2: F T and T F. As we only want 2 from 4, the probability of having different outcomes , and each of them has an equal probability of 1/4:

P(diff outcomes) = P (F T or T F) = 1/4 + 1/4 = 1/2

So, the probability of different outcomes is 1/2.

Then we need to get the probability of having an odd number from the spinning, and it is really similar to the coin event.

Our universe is: 1, 2, 3, 4

from these, only two numbers are odd:1 and 3

As any of them has the same probability of 1/4, the probability of odd number is:

P(odd) = P (1 or 3) = 1/4 + 1/4 = 1/2

So, as both events have a probability if 1/2 and are independent:

P(diff outcomes AND odd) =  P(different outcomes) * P(odd) = 1/2 * 1/2 = 1/4

Option C

no not all of them.

step-by-step explanation:

some of them have a square base.

idk

step-by-step explanation:

i don't know