Your science teacher recently gave a quiz to 28 students present in class. the class average was an 82.5. five students that were absent made up the quiz after schoolamd their scores were a 78, 89,92,,99, & 63. find the new class average with the newscores

Total students in the class who got the quiz = 28

The average of the class average was = 82.5

Five students that were absent made up the quiz after school and their scores were a 78, 89,92,99, & 63.

The formula for an average= (sum of values) / (count of values)

As the average is given as 82.5 and there were 28 students, so sum of the 28 values will be =

Total students of the class = 28+5(absent) = 33

For 33 students the total score was = 2310 +(78+89+92+99+63)

= 2731

So, average for 33 students will be = or 82.76

So, the new class average is 82.76

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: