An ac generator with peak voltage 100 volts is placed across a 10-? resistor. what is the average power dissipated?

The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2 / R = (100 * 100) / (2 * 10) = 500 W

The chemical reactions lab we did is typically called a "copper plating lab,  because the acid solution cleaned the pennies and made the copper look shinier;   the acid solution cleaned the paperclips and made them look like pennies;   &   the copper from the pennies was removed, and then added to the paperclips.