What is the solution to y=2x^2-8x+8

x = 2 and x = 2

Step-by-step explanation:

Simplify this problem by factoring out the coefficient 2:

y=2x^2-8x+8 => 2(x^2 - 4x + 4)

Note that x^2 - 4x + 4 is a perfect square:  (x - 2)^2.

y=2x^2-8x+8 = 2(x - 2)^2

Setting this last result = to 0, we get y = 2(x - 2)^2 = 0, which has a repeated solution:  x = 2 and x = 2.