Ahardware store orders at most $2,500 worth of concrete and sand. the store needs to make a profit of at least $2,750 on the order. the possible combinations of concrete and sand for this order are given by this system of inequalities, where c = pounds of concrete and s = pounds of sand: 6c + 2s ≤ 2,500 4.50c + 3s ≥ 2,750 which graph's shaded region represents the possible combinations of concrete and sand for this order?

The below graph's shaded region represents the possible combinations of concrete and sand for this order

Step-by-step explanation:

Here, the system of inequality that represents the given situation is,

6c + 2s ≤ 2,500 --------(1)

4.50c + 3s ≥ 2,750 -------(2)

Where c = pounds of concrete,

s = pounds of sand

Now, The related equation of the above inequalities are,

6c + 2s = 2500

4.50c + 3s = 2750

By solving the above equations,

We get, ,

Thus, the intersection point of the inequalities =

Now, At (0,0) ,

inequality (1), 6×0 + 2×0≤ 2500 ⇒ 0 ≤ 2500 ( true)

Hence, the shaded region of inequality contains the origin.

Similarly, At (0,0), inequality (2) is false,

⇒ The shaded region of inequality (2) does not contain the origin.

Thus, By the above explanation we can plot the shaded region of the system of the given inequalities.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.