Given the partial equation: H2O2 + ClO2 → O2 + ClO2−, balance the reaction in basic solution using the half-reaction method and fill in the coefficients. The missing blanks represent H2O, H+, or OH-, as required to balance the reaction. Enter the coefficients as integers, using the lowest whole numbers. If the coefficient for something is "1", make sure to type that in and not leave it blank. Enter only the coefficients. H2O2 + ClO2 + → O2 + ClO2− +

Answer :  The balanced chemical equation in basic medium will be,

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given chemical reaction is,

The oxidation-reduction half reaction will be :

Oxidation :

Reduction :

Now balance the hydrogen atom.

Oxidation :

Reduction :

To neutralizing the hydrogen ion by adding hydroxide ion on both side.

Oxidation :

Reduction :

Hydrogen ion hydroxide ion combine to form water.

Oxidation :

Reduction :

Now balance the charge.

Oxidation :

Reduction :

The charges are not balance on both side of the reaction. We are multiplying reduction reaction by 2 and then added both equation, we get the balanced redox reaction.

Oxidation :

Reduction :

The balanced chemical equation in basic medium will be,

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole