Melinda can paint 1/4 of a wall in the same time that desiree can paint 2/5 of a wall. how much of a wall will melinda have painted when desiree has finished painting 1 wall?

Melinda will paint 5/8 part of a wall when Desiree has finished painting 1 wall.

Step-by-step explanation:

It is given that:

Melinda can paint 1/4 of a wall in the same time that Desiree can paint 2/5 of a wall.

Let 't' be the time taken by Melinda and Desiree to paint 1/4 and 2/5 of a wall respectively.

Now the time taken by Desiree to paint 1 wall will be:

2/5 of wall= t

1 wall= (5/2) t

Now in this time ( i.e. 5/2 t) the part of a wall painted by Melinda will be:

As Melinda takes--  t time to paint= 1/4 of a wall

                              5/2 t she will paint= (5/2)×(1/4) of a wall= (5/8) of a wall.

Hence Melinda will paint 5/8 part of a wall when Desiree has finished painting 1 wall.

choice b

step-by-step explanation:

f(x) = 88x^2 -264x + 300

the line of symmetry of a parabola is defined by

h = -b/2a

where ax^2 +bx+c=0

so

h = - -264/ (2*88)

h = 3/2

so x = 1.5