Which value of a solves the equation a^-2 = 1/100

a = 10 or a = -10

Step-by-step explanation:

a^-2 = 1/100

We know 100 = 10^2

a^-2 = 1/10^2

We know 1/b^c = b^-c

1/a^2 = 1/ 10^2

Multiply by a^2 on each side

a^2 *1/a^2 = 1/ 10^2 *a^2

1 = a^2/10^2

Multiply by 10^2 on each side

1 0^2= a^2/10^2 * 10^2

10^2 = a^2

Take the square root of each side

sqrt(10^2) = sqrt(a^2)

±10 =a

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.