What is the equation in point-slope form of the line that passes through the point (−1, −4) and has a slope of –3

Point-slope form:

y - y₁ = m(x - x₁)              "m" is the slope

You know:

m = -3

(x₁ , y₁) = (-1, -4)

So you can plug this into the equation:

y - y₁ = m(x - x₁)      

y - (-4) = -3(x - (-1)

y + 4 = -3(x + 1)

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)