Solve for x. −2x + 3b > 5 x > the quantity 3 times b minus 5 all over 2 x > the quantity 5 minus 3 times b all over negative 2 x < the quantity 3 times b plus 5 all over 2 x < the quantity negative 3 times b plus 5 all over negative 2

x < the quantity negative 3 times b plus 5 all over negative 2

Step-by-step explanation:

−2x + 3b > 5

Subtract 3b from both side.

-2x +3b -3b > 5-3b

-2x > 5-3b

Divide by -2 on both sides, remember to flip the inequality since we are dividing by a negative

-2x/-2 < 5/-2 - 3b/-2

x < (5-3b)/-2

x< (-3b+5)/-2

Re write in words.

x is less than the quantity  negative 3 times b plus 5  all over  negative 2