Factor x^4 + xy^3 + x^3 + y^3. hint, first factor a monomial. explain !

Pull an x from the first two terms

x(x^3 + y^3) + (x^3 + y^3)   Now x^3 + y^3 is a common factor.

(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors

(x^3 + y^3) = (x + y)(x^2 - xy + y^2)

Which means you could write original polynomial as

(x + y)(x^2 - xy + y^2)(x + 1)

Part B

You factored the x out of xy^3 so that you would have a common factor (x^3 + y^3) to pull out as a common factor for the whole polynomial.

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.