Apunter kicked a 41-yard punt. the path of the football can be modeled by y = -0.035x^2 + 1.4x + 1, where x is the distance (in yards) the football is kicked and y is the height (in yards) the football is kicked. 1. does the graph open up or down? 2. does the graph have a maximum value or a minimum value? 3. graph the quadratic function.4. find the maximum height of the football. im really struggling.

The graph is a parabola and  will open downwards.

It will have a maximum value.

To find the maximum value we convert to vertex form:-

y = -0.035x^2 + 1.4x + 1

y = -0.035(x^2 - 40x) + 1

y = -0.035[ (x - 20)^2 - 400)  + 1

y = -0.035(x - 20)^2  + 15

The maximum height of the ball is 15 yards

Open down, Maximum value, attached image, y=15 yards

Step-by-step explanation:

1) Open down. This can be figured out by the sign of the quadratic term (if negative open down if positive the parabola opens up). In this case -0.035 is negative

2) Maximum value. Since it opens down it has a maximum value

3) Attached image

4) In vertex form

y = -0.035x^2 + 1.4x + 1

y = -0.035(x^2 - 40x) + 1

y = -0.035[ (x - 20)^2 - 400)  + 1

y = -0.035(x - 20)^2  + 15

For x=20 yards then y=15 yards (maximum yard). In the graph we can see that the max height is 15 yards also

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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it should be a and d. lmk if i'm wrong xd