Is it possible to place 59 cans into three boxes so that the third box has 9 more cans than the first box and the second box has 4 less cans than the third box?

YES!

Step-by-step explanation:

First Box: x

Second Box: (x + 9) - 4  = x + 5

Third Box: x + 9

Total: 59

First Box + Second Box + Third Box = Total

     x        +       x + 5              x + 9      =   59

3x + 14 = 59

      -14  -14        

3x       =  45

÷3          ÷3        

        x = 15

Since 15 is a whole number (not a fraction), then it is possible.                            

80 the answer is 80

step-by-step explanation:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: