Two numbers sum to 38. twice the first subtracted from the second is 2. find the numbers

Two numbers are A & B

A+ B = 38

B- 2A= 2

B= 2+2A  

A+ 2+2A =38

3A = 38-2= 36

A= 12

B=2+2A= 2+ 2*12= 26

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

50.6

step-by-step explanation: