Two cars traveled equal distances in different amounts of time. car a traveled the distance in 4 h, and car b traveled the distance in 4.5 h. car b traveled 5 mph slower than car a. (the formula r⋅t=d , where r is the rate of speed, t is the time, and d is the distance can be used.) how fast did car b travel? enter your answer in the box. mph

x = rate in mph

distance (car A) = (x +5) * 4

distance (car B) = x *4.5

(x +5) *4 = 4.5x

4x + 20 = 4.5x

20 = .5x

x = rate = 40 mph

car B traveled at 40 mph

i think its 7.6

if so your welcome

1. she sold more on day 2 because if you turn .85 into a fraction{85/100} and you give 7/9 and 85/100 the same denominator{180} you can see which one has the bigger numerator and that one will be the most sold.

2. yes it is in simplest form, because if you look at 38 and 53 's greatest common factor, you cant find one so you cant reduce it

3. no, this is not a prime factorization because the numbers are not all prime numbers, the correct prime factorization is:   2 x 5 x 2

4.   in 12 days he will run and play trumpet again

work 4 4: 123123123123

                123412341234     in 12 days he will play the trumpet and run on the same day

step-by-step explanation:

i am normally pretty good at math, im new to this site, but im 1 grade ahead in my math, i luv math try my answers out, see how they work