Which values of p and q result in an equation with no solutions? px - 45= qx+75 a. p=-45 and q=-75 b. p=45 and q=-15 c. p=15 and q=15 d. p=15 and q=75

Px - 45 = QX + 75

Px - Qx = 75 + 45 = 120

A. If P = - 45 and Q = - 75, then

- 45x + 75 x = 120

30x = 120 and x = 40

B. If P = 45 and Q = - 15, then

45x - 15x = 120

30x = 120

x = 40

D. If P = 15 and Q = 75, then

15x - 75x = 120

- 60x = 120

x = - 2

C. If P = 15 and Q = 15, then

15x - 15x = 120

0 = 120 which is absurd.

Hence, P = 15 and Q = 15 result in an equation with no solution.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4