Truck A leaves station 1 at 9:00 a. m. and travels at the rate of 60 kph. After 2 hours, Truck B leaves the same station and travels in the same direction at the rate of 80 kph. At what time will Truck B overtake Truck A?

Step-by-step explanation:

Given

Truck A speed is

Truck B speed is

Truck A leaves 2 hours before truck B

Distance traveled in the 2 hour

Suppose Truck B will catch truck A after t hours

Overtake time is

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²