One angle of a triangle measures 10 degrees more than the second. the measure of the third angle is twice the sum of the first two angles. find the measure of each angle.

Let x = second angle
let x + 10 = first angle
let 2( (x) + (x+10) ) = third angle.
Since the interior of a triangle equals 180° then,






Inputting the value of x gives us each angle.

second angle = 25°
first angle = x + 10 = 25 + 10 = 35°
third angle = 2( (x) + (x+10) ) = 2( (25) + (25+10) )
= 110°

For the first question the answer is a, for the second c, for the third d, for the 4th b, for the 5th a