Asap 70 points question 1) d = {[x, f(x)]: (-1, 3), (0, 2), (1, 3), (2, 6), (3, 11)} write the rule for f(x). question 2) given: f(x) = 3x 2 + 1, g(x) = 2x - 3, h(x) = x f(-2) = question 3) given: f(x) = 3x 2 + 1, g(x) = 2x - 3, h(x) = x f(x) + g(x) =

question 1)

D = {[x, f(x)]: (-1, 3), (0, 2), (1, 3), (2, 6), (3, 11)} Write the rule for f(x).

when x = 0 , f(x) = 2

f(x) = x^2 + 2 this is the rule

question 2)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(-2) = 3(-2)^2 + 1 = 12 + 1 = 13

F(-2) = 13

question 3)

Given: F(x) = 3x 2 + 1, G(x) = 2x - 3, H(x) = x

F(x) + G(x) = 3x^2 + 1 + 2x - 3

F(x) + G(x) = 3x^2 + 2x - 2

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5